0=6x^2+40x+50

Solution for 0=6x^2+40x+50 equation:

0=6x^2+40x+50

We move all terms to the left:

0-(6x^2+40x+50)=0

We add all the numbers together, and all the variables

-(6x^2+40x+50)=0

We get rid of parentheses

-6x^2-40x-50=0

a = -6; b = -40; c = -50;
Δ = b2-4ac
Δ = -402-4·(-6)·(-50)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-20}{2*-6}=\frac{20}{-12}
=-1+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+20}{2*-6}=\frac{60}{-12}
=-5
$